In my cement plant, the mill feed is the tailings from the separator. The average surface area of the mill feed is 85 m2/kg. If the target surface area of the cement I produce is 360 m2/kg, what should be my mill outlet surface area?
lalbatros
If {f,c,r} denote the feed to the separator, cement and reject flow rate, and
if {F,C,R} denote the feed, cement and reject specific surface,
then the surface balance reads:
f F = c C + r R
and the mass balance reads
f = c + r
You can use these two balance equations to solve your problem, if you have the necessary data. In the result, you might also use the definition of the circulating load:
Circ = f/cThe result is:
F = c * 1/Circ + r * (1-1/Circ)
and with your numbers:
F = 360 * 1/Circ + 85 * (1-1/Circ)
The actual circulating load should be either measured, or guessed, or derived from a model or from empirical knowledge.