how can i calculate water required to cool down the gasses after PH (280) to (150 degree
)
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Dear Mr. Khan
water l/h =Q.R.S.DT/[(100-Tw)+539]
where Q= gas flow m3/hr
R= gas density kg/m3
s= specific heat of gas
DT = gas cooling temp. from - to deg.
Tw= water temp. deg.
engineer
abid khan
THANKS ALOT